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The common-ion effect primarily describes an increase in the solubility of an ionic precipitate when a soluble compound sharing an ion is added.
Answer: False
Explanation: The common-ion effect describes a *reduction* in the solubility of an ionic precipitate when a common ion is added, not an increase.
Le Chatelier's principle explains the common-ion effect by stating that equilibrium shifts to counteract a disturbance, such as the addition of a common ion.
Answer: True
Explanation: Le Chatelier's principle accurately describes how the equilibrium of a sparingly soluble salt shifts to reduce the concentration of a common ion, leading to decreased solubility.
The common-ion effect causes an increase in the concentration of dissolved ions of a sparingly soluble salt.
Answer: False
Explanation: The common-ion effect causes a *decrease* in the concentration of dissolved ions of a sparingly soluble salt, as the equilibrium shifts towards precipitation.
The common-ion effect is exclusively observed with salts and does not apply to weak electrolytes.
Answer: False
Explanation: The common-ion effect is observed with both sparingly soluble salts and weak electrolytes, as both involve an equilibrium between ionized and un-ionized species.
Adding a common ion to a solution of a sparingly soluble salt will generally lead to increased precipitation of that salt.
Answer: True
Explanation: According to Le Chatelier's principle, the addition of a common ion shifts the dissolution equilibrium towards the formation of more solid precipitate, thus increasing precipitation.
The common-ion effect applies to the solubility of both salts and strong electrolytes.
Answer: False
Explanation: The common-ion effect applies to sparingly soluble salts and weak electrolytes, not strong electrolytes, which are already fully dissociated.
What is the fundamental definition of the common-ion effect in chemistry?
Answer: It describes the reduction in solubility of an ionic precipitate when a soluble compound, which shares an ion with the precipitate, is added to the solution.
Which scientific principle directly explains the behavior observed in the common-ion effect?
Answer: Le Chatelier's principle
How does the common-ion effect specifically influence the solubility of an ionic precipitate?
Answer: It decreases the solubility by causing more of the precipitate to form.
Besides salts, what other type of chemical compound commonly demonstrates the common-ion effect?
Answer: Weak electrolytes
What happens to the concentration of both ions of a sparingly soluble salt when an additional amount of one of its common ions is introduced into a solution?
Answer: The concentration of both ions decreases due to increased precipitation.
Hydrogen sulfide (H₂S) is a strong electrolyte that completely ionizes in aqueous solutions.
Answer: False
Explanation: Hydrogen sulfide (H₂S) is a weak electrolyte, meaning it only partially ionizes in aqueous solutions, establishing an equilibrium.
The equilibrium reaction for hydrogen sulfide ionization shows it reversibly dissociating into H⁺ and HS⁻.
Answer: True
Explanation: The partial ionization of H₂S is represented by the reversible equilibrium: H₂S(aq) ⇌ H⁺(aq) + HS⁻(aq).
The acid dissociation constant (K_a) for H₂S is expressed as K_a = [H₂S] / ([H⁺][HS⁻]).
Answer: False
Explanation: The correct expression for the acid dissociation constant (K_a) for H₂S is K_a = ([H⁺][HS⁻]) / [H₂S], where products are in the numerator and reactants in the denominator.
Hydrochloric acid (HCl) is a strong electrolyte that ionizes almost completely in solution.
Answer: True
Explanation: As a strong electrolyte, HCl dissociates nearly 100% into H⁺ and Cl⁻ ions when dissolved in water.
When HCl is added to an H₂S solution, chloride ions (Cl⁻) act as the common ion.
Answer: False
Explanation: When HCl is added to an H₂S solution, the hydrogen ion (H⁺) acts as the common ion, as both H₂S and HCl produce H⁺ in solution.
The addition of H⁺ ions from HCl shifts the H₂S dissociation equilibrium to the right, increasing HS⁻ concentration.
Answer: False
Explanation: The addition of H⁺ ions shifts the H₂S dissociation equilibrium to the *left*, increasing the concentration of un-ionized H₂S and *decreasing* the HS⁻ concentration, according to Le Chatelier's principle.
A buffer solution is characterized by containing a strong acid and its conjugate base.
Answer: False
Explanation: A buffer solution is characterized by containing a *weak* acid and its conjugate base, or a weak base and its conjugate acid, not a strong acid.
Adding a conjugate ion to a buffer solution will always decrease its pH.
Answer: False
Explanation: Adding a conjugate base to a weak acid buffer will *increase* the pH, while adding a conjugate acid to a weak base buffer would decrease it. The effect depends on the nature of the conjugate ion added.
Sodium acetate (NaCH₃CO₂) is a weak electrolyte that partially dissociates in solution.
Answer: False
Explanation: Sodium acetate (NaCH₃CO₂) is a strong electrolyte, meaning it dissociates *completely* into Na⁺ and CH₃CO₂⁻ ions in solution.
Acetic acid (CH₃CO₂H) is a strong acid that ionizes completely in solution.
Answer: False
Explanation: Acetic acid (CH₃CO₂H) is a *weak* acid, meaning it only ionizes slightly and establishes an equilibrium in solution.
When sodium acetate and acetic acid are together, acetate ions from sodium acetate suppress the ionization of acetic acid.
Answer: True
Explanation: The acetate ions (CH₃CO₂⁻) from the strong electrolyte sodium acetate act as a common ion, shifting the acetic acid dissociation equilibrium to the left and suppressing its ionization.
In an acetate buffer, the common-ion effect decreases the percent dissociation of acetic acid and increases the solution's pH.
Answer: True
Explanation: The common-ion effect reduces the extent of acetic acid ionization (decreasing percent dissociation) and, by reducing H⁺ concentration, leads to an increase in the solution's pH.
The hydronium concentration in a solution containing both acetic acid and sodium acetate is higher than in a solution containing only acetic acid.
Answer: False
Explanation: The common-ion effect suppresses the ionization of acetic acid, resulting in a *decreased* hydronium (H⁺) concentration compared to a solution containing only acetic acid.
When HCl is added to an H₂S solution, the concentration of un-ionized H₂S molecules decreases.
Answer: False
Explanation: The addition of HCl shifts the H₂S dissociation equilibrium to the left, causing an *increase* in the concentration of un-ionized H₂S molecules.
How is hydrogen sulfide (H₂S) classified based on its ionization behavior in an aqueous solution?
Answer: Weak electrolyte
What is the correct equilibrium reaction that represents the partial ionization of hydrogen sulfide in water?
Answer: H₂S ⇌ H⁺ + HS⁻
According to the law of mass action, how is the acid dissociation constant (K_a) for hydrogen sulfide mathematically expressed?
Answer: K_a = ([H⁺][HS⁻]) / [H₂S]
What is the nature of hydrochloric acid (HCl) as an electrolyte?
Answer: It is a strong electrolyte, ionizing almost completely in solution.
When hydrochloric acid is added to an H₂S solution, which ion acts as the common ion?
Answer: Hydrogen ion (H⁺)
According to Le Chatelier's principle, how does the addition of H⁺ ions from HCl affect the equilibrium of H₂S dissociation?
Answer: The equilibrium shifts to the left, increasing un-ionized H₂S.
What are the two main components that characterize a buffer solution?
Answer: An acid and its conjugate base, or a base and its conjugate acid.
How does the common-ion effect manifest when a conjugate ion is added to a weak acid buffer solution?
Answer: It causes a change in the pH, for example, adding a conjugate base to a weak acid buffer will increase the pH.
What is the dissociation behavior of sodium acetate (NaCH₃CO₂) when dissolved in a solution?
Answer: It dissociates completely as a strong electrolyte.
How does acetic acid (CH₃CO₂H) behave as an electrolyte in solution?
Answer: It is a weak acid, ionizing slightly.
When both sodium acetate and acetic acid are present, how do the acetate ions from sodium acetate influence the ionization of acetic acid?
Answer: They suppress the ionization of acetic acid by shifting its equilibrium to the left.
What is the overall effect on the percent dissociation of acetic acid and the pH of the solution due to the common-ion effect in an acetate buffer?
Answer: Percent dissociation decreases, pH increases.
How does the hydronium (H⁺) concentration in a common-ion solution containing acetic acid and sodium acetate compare to a solution containing only acetic acid?
Answer: The hydronium concentration will be decreased.
When HCl is added to an H₂S solution, what is the resulting impact on the concentration of un-ionized H₂S molecules?
Answer: The concentration of un-ionized H₂S molecules increases.
Which of the following is NOT a characteristic of a buffer solution?
Answer: Contains a strong acid and a strong base.
The chemical formula for barium iodate is Ba(IO₄)₂, and its K_sp is 1.57 x 10⁻⁹.
Answer: False
Explanation: The chemical formula for barium iodate is Ba(IO₃)₂, not Ba(IO₄)₂. The K_sp value provided is correct for Ba(IO₃)₂.
The solubility of barium iodate in pure water is 7.32 x 10⁻⁴ M.
Answer: True
Explanation: Calculations show that the molar solubility of Ba(IO₃)₂ in pure water, derived from its K_sp, is indeed 7.32 x 10⁻⁴ M.
The solubility of barium iodate is approximately ten times smaller in a 0.0200 M barium nitrate solution compared to pure water.
Answer: False
Explanation: The solubility of barium iodate in a 0.0200 M barium nitrate solution (1.40 x 10⁻⁴ M) is approximately *five* times smaller than its solubility in pure water (7.32 x 10⁻⁴ M), not ten times.
In water treatment, sodium chloride is added to precipitate calcium carbonate and reduce water hardness.
Answer: False
Explanation: In water treatment, *sodium carbonate* (Na₂CO₃) is added to precipitate calcium carbonate (CaCO₃) and reduce water hardness, not sodium chloride.
The calcium carbonate precipitate from water treatment is a valuable by-product used in products like toothpaste.
Answer: True
Explanation: The finely divided calcium carbonate obtained from water treatment is a high-purity product with commercial applications, including its use as an abrasive in toothpaste.
The salting-out process in soap manufacturing uses the common-ion effect by adding sodium chloride to increase the solubility of soap salts.
Answer: False
Explanation: The salting-out process uses the common-ion effect to *reduce* the solubility of soap salts, causing them to precipitate, rather than increasing their solubility.
Waters with high sodium ion concentrations, like sea water, make soap less effective due to the common-ion effect.
Answer: True
Explanation: The high concentration of sodium ions (Na⁺) in sea or brackish water acts as a common ion with the sodium salts of fatty acids (soap), reducing soap's solubility and thus its effectiveness.
The solubility of barium iodate in a 0.0200 M barium nitrate solution is 1.40 x 10⁻⁴ M.
Answer: True
Explanation: Due to the common-ion effect from Ba²⁺ ions supplied by barium nitrate, the solubility of barium iodate is reduced to 1.40 x 10⁻⁴ M.
The common-ion effect can be used to remove hardness-causing calcium ions from water.
Answer: True
Explanation: By adding a common ion (carbonate from sodium carbonate), sparingly soluble calcium carbonate precipitates, effectively removing calcium ions and reducing water hardness.
Soaps are generally potassium salts of fatty acids.
Answer: False
Explanation: Soaps are generally *sodium* salts of fatty acids, although potassium salts also exist and are used in liquid soaps.
The K_sp value for barium iodate is 1.57 x 10⁻⁹.
Answer: True
Explanation: The solubility product constant (K_sp) for barium iodate, Ba(IO₃)₂, is indeed 1.57 x 10⁻⁹.
What is the chemical formula for barium iodate and its solubility product constant (K_sp)?
Answer: Ba(IO₃)₂, K_sp = 1.57 x 10⁻⁹
Quantitatively, how much is the solubility of barium iodate reduced when it is dissolved in a 0.0200 M barium nitrate solution compared to pure water?
Answer: It is reduced to 1.40 x 10⁻⁴ M, which is approximately five times smaller.
In water treatment, which specific chemical is added to raw water to facilitate the precipitation of calcium carbonate?
Answer: Sodium carbonate
What is a commercial use for the very pure and finely divided calcium carbonate precipitate obtained from water treatment?
Answer: In the manufacture of toothpaste
How does the common-ion effect contribute to the salting-out process in soap manufacturing?
Answer: It reduces the solubility of soap salts by adding sodium chloride, causing them to precipitate.
Why do waters containing significant amounts of sodium ions, such as sea or brackish water, diminish the effectiveness of soap?
Answer: The excess sodium ions reduce the solubility of soap salts due to the common-ion effect.
What is the approximate ratio of barium iodate's solubility in pure water compared to its solubility in a 0.0200 M barium nitrate solution?
Answer: The solubility in pure water is about five times higher.
How is the common-ion effect utilized in water treatment to reduce water hardness?
Answer: By adding sodium carbonate to precipitate sparingly soluble calcium carbonate.